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AP Calculus AB/BC · Mathematics · Lesson 5.8

5.8 Sketching f and its derivatives

Level
Advanced Placement (AP)
Reading time
10 min reading
Errata

Abstract

The three graphs are linked: where f′=0f'=0, ff has a horizontal tangent; where f′>0f'>0, ff rises; where f′′>0f''>0, ff is concave up.

Concept preview

What you will be able to do

  1. 01Translate between the graphs of ff, f′f', and f′′f'': read where ff rises or falls from the sign of f′f', and read the concavity of ff from the sign of f′′f''.
  2. 02Sketch the graph of f′f' from a graph of ff (and vice versa), placing zeros of f′f' at the turning points of ff and zeros of f′′f'' at the inflection points of ff.
  3. 03Match a function to the correct graph of its derivative, and avoid the pervasive error of confusing a graph of ff with a graph of f′f'.

Start with the link between ff and f′f'. At every input xx, the VALUE (height) of f′f' equals the SLOPE of ff. So where the graph of ff is rising, f′f' sits above the axis (positive); where ff is falling, f′f' sits below the axis (negative); and where ff has a horizontal tangent — a local max or min — f′f' touches zero, crossing the xx-axis. Steep parts of ff push f′f' far from the axis; gentle parts keep f′f' near it. Reading f′f' off ff is therefore a matter of tracing the steepness of ff and plotting it as a height.

All-Access Plan

5.8 Sketching f and its derivatives

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