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AP Calculus AB/BC · Mathematics · Lesson 5.9

5.9 Connecting f, f′, and f″

Level
Advanced Placement (AP)
Reading time
11 min reading
Errata

Abstract

Given any one of the three graphs, you can deduce features of the others — position, slope, and bending are all connected.

Concept preview

What you will be able to do

  1. 01Read across the three graphs ff, f′f', and f′′f'' fluently: translate “ff increasing” into “f′>0f'>0”, “ff concave up” into “f′′>0f''>0 (equivalently f′f' increasing)”, and locate local extrema and inflection points on whichever graph is in front of you.
  2. 02Reconstruct qualitative facts about ff from a graph or table of f′f' alone (or of f′′f'' alone), using must-be-true reasoning rather than guessing at the shape of ff.
  3. 03Diagnose and avoid the single most common error in this topic — mistaking the graph of f′f' for the graph of ff — by naming, for every conclusion, which derivative controls it.

Begin with the first derivative. The value of f′(x)f'(x) is the slope of ff at xx, so its SIGN is a verdict on direction: where f′>0f'>0 the graph of ff is climbing, where f′<0f'<0 it is descending, and where f′=0f'=0 the tangent is momentarily level. Because a smooth graph can only switch from rising to falling by passing through a level instant, the candidates for local maxima and minima of ff are exactly the xx-values where f′f' crosses zero. But crossing zero is not enough by itself — you must check HOW f′f' crosses. If f′f' goes from positive to negative, ff was rising then falling, so that point is a local maximum. If f′f' goes from negative to positive, ff was falling then rising, so it is a local minimum. If f′f' merely touches zero without changing sign, ff has a flat spot but no extremum there.

All-Access Plan

5.9 Connecting f, f′, and f″

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