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AP Calculus AB/BC · Mathematics · Lesson 5.4

5.4 The first derivative test

Level
Advanced Placement (AP)
Reading time
11 min reading
Errata

Abstract

At a critical point, watch how the slope changes sign: from up to down is a peak; from down to up is a valley.

Concept preview

What you will be able to do

  1. 01State the First Derivative Test: at a critical number cc, if f′f' changes from ++ to −- then f(c)f(c) is a local (relative) MAXIMUM, if f′f' changes from −- to ++ then f(c)f(c) is a local MINIMUM, and if f′f' does NOT change sign then cc is neither.
  2. 02Justify a classification of a relative extremum with an explicit sign analysis of f′f' on both sides of the critical number, rather than merely asserting max or min.
  3. 03Apply the test to polynomials — finding every critical number, testing the sign of f′f' just before and just after each, and reporting the location and type of each relative extremum.

Suppose cc is a critical number of a continuous function ff (so f′(c)=0f'(c)=0 or f′(c)f'(c) is undefined). Look at the sign of f′f' immediately to the LEFT of cc and immediately to the RIGHT of cc. Three things can happen. (1) If f′f' changes from POSITIVE to NEGATIVE as xx increases through cc, then ff rises up to cc and falls afterward, so ff has a local MAXIMUM at cc. (2) If f′f' changes from NEGATIVE to POSITIVE, then ff falls into cc and rises afterward, so ff has a local MINIMUM at cc. (3) If f′f' does NOT change sign — it is positive on both sides, or negative on both sides — then ff keeps going the same direction and cc is NEITHER a max nor a min.

All-Access Plan

5.4 The first derivative test

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