Skip to main content
Dr. Shreyank Educare
Curriculum-aligned learning support — not an official school, university, or ministry-approved course, and not a replacement for official credit.
BackTopic 12/12
0%
Unit 5Lesson navigation

AP Calculus AB/BC · Mathematics · Lesson 5.12

5.12 Behaviours of implicit relations

Level
Advanced Placement (AP)
Reading time
9 min reading
Errata

Abstract

For a curve given implicitly, the tangent slope comes from implicit differentiation.

Concept preview

What you will be able to do

  1. 01Use implicit differentiation to find dydx\dfrac{dy}{dx} for a relation, treating yy as a function of xx so every yy-term carries a dydx\dfrac{dy}{dx} factor.
  2. 02Locate HORIZONTAL tangents where the numerator of dydx\dfrac{dy}{dx} is zero and VERTICAL tangents where the denominator is zero, checking that the point lies on the curve.
  3. 03Compute the second derivative d2ydx2\dfrac{d^2y}{dx^2} of an implicit relation and use its sign to determine concavity of curves such as x2+y2=r2x^2+y^2=r^2, xy=kxy=k, and ellipses.

The governing idea of implicit differentiation is a single sentence: along the curve, yy is a function of xx, so differentiating any term that contains yy requires the chain rule and produces a dydx\dfrac{dy}{dx} factor. Differentiating x2x^2 gives 2x2x; differentiating y2y^2 gives 2ydydx2y\dfrac{dy}{dx} — NOT just 2y2y. The dydx\dfrac{dy}{dx} is the price of the chain rule, and it is exactly what a careless solver drops.

All-Access Plan

5.12 Behaviours of implicit relations

This lesson's full explanation, worked examples, quiz and practice are locked. Full access is on the All-Access Plan.

Log in or start free and you will return right here.