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AP Calculus AB/BC · Mathematics · Lesson 6.3

6.3 Riemann sums and definite-integral notation

Level
Advanced Placement (AP)
Reading time
9 min reading
Errata

Abstract

As the rectangles get infinitely thin, the Riemann sum becomes exact — that limit is the definite integral.

Concept preview

What you will be able to do

  1. 01Build a Riemann sum by slicing [a, b][a,\,b] into nn equal pieces of width Δx=b−an\Delta x=\dfrac{b-a}{n}, choosing a sample point xix_i in each, and writing the total in sigma notation as ∑i=1nf(xi) Δx\displaystyle\sum_{i=1}^{n} f(x_i)\,\Delta x.
  2. 02Explain why the limit lim⁡n→∞∑i=1nf(xi) Δx\displaystyle\lim_{n\to\infty}\sum_{i=1}^{n} f(x_i)\,\Delta x produces one exact number — the definite integral ∫abf(x) dx\displaystyle\int_a^b f(x)\,dx — and identify the roles of the ∫\int sign, the limits aa and bb, and the dxdx.
  3. 03Translate fluently in both directions between a limit of a Riemann sum and the definite-integral notation it stands for, reading off ff, aa, and bb from either form.

Suppose we want the area under y=f(x)y=f(x) between x=ax=a and x=bx=b, where ff is positive. Start by cutting the interval [a, b][a,\,b] into nn equal subintervals. Each subinterval has the same width, which we call Δx\Delta x. Because the total length b−ab-a is shared equally among nn pieces, Δx=b−an\Delta x=\dfrac{b-a}{n}. On each subinterval we build a rectangle: its width is Δx\Delta x and its height is the value of ff at some chosen point xix_i inside that subinterval. The area of the ii-th rectangle is therefore height times width, f(xi) Δxf(x_i)\,\Delta x, and the combined area of all nn rectangles approximates the area under the curve.

All-Access Plan

6.3 Riemann sums and definite-integral notation

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