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AP Calculus AB/BC · Mathematics · Lesson 6.8

6.8 Antiderivatives and indefinite integrals

Level
Advanced Placement (AP)
Reading time
8 min reading
Errata

Abstract

Antidifferentiation reverses the derivative.

Concept preview

What you will be able to do

  1. 01Apply the reverse-power rule ∫xn dx=xn+1n+1+C\displaystyle\int x^n\,dx=\frac{x^{n+1}}{n+1}+C for every n≠−1n\neq -1, and handle the single excluded case with ∫1x dx=ln⁡∣x∣+C\displaystyle\int\frac1x\,dx=\ln|x|+C.
  2. 02Recall and use the basic antiderivatives of sin⁡x\sin x, cos⁡x\cos x, and exe^x, together with the constant-multiple rule ∫kf=k∫f\int k f = k\int f and the sum rule ∫(f+g)=∫f+∫g\int (f+g)=\int f+\int g, to antidifferentiate polynomials and combinations.
  3. 03Read and write indefinite-integral notation ∫f(x) dx=F(x)+C\int f(x)\,dx=F(x)+C correctly, always including the constant of integration +C+C, and explain what the constant represents.

To differentiate a power you multiply by the exponent and drop it by one: ddxxk=k xk−1\tfrac{d}{dx}x^{k}=k\,x^{k-1}. Antidifferentiation reverses both moves — you RAISE the exponent by one and DIVIDE by the new exponent. That gives the reverse-power rule: ∫xn dx=xn+1n+1+C,n≠−1.\int x^n\,dx=\frac{x^{n+1}}{n+1}+C,\qquad n\neq -1. You can verify it instantly by differentiating the right-hand side: ddx(xn+1n+1)=(n+1)xnn+1=xn\tfrac{d}{dx}\left(\tfrac{x^{n+1}}{n+1}\right)=\tfrac{(n+1)x^{n}}{n+1}=x^{n}, exactly the integrand. This single formula covers positive powers, negative powers, and fractional (root) powers alike. For example ∫x5 dx=x66+C\int x^5\,dx=\tfrac{x^6}{6}+C; ∫x−2 dx=x−1−1+C=−1x+C\int x^{-2}\,dx=\tfrac{x^{-1}}{-1}+C=-\tfrac1x+C; and ∫x dx=∫x1/2 dx=x3/23/2+C=23x3/2+C\int \sqrt{x}\,dx=\int x^{1/2}\,dx=\tfrac{x^{3/2}}{3/2}+C=\tfrac23 x^{3/2}+C.

All-Access Plan

6.8 Antiderivatives and indefinite integrals

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