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AP Calculus AB/BC · Mathematics · Lesson 6.7

6.7 Evaluating definite integrals with the FTC

Level
Advanced Placement (AP)
Reading time
9 min reading
Errata

Abstract

To get the exact area, find an antiderivative and subtract its values at the two limits — no rectangles needed.

Concept preview

What you will be able to do

  1. 01State the evaluation form of the Fundamental Theorem of Calculus: if FF is any antiderivative of a continuous function ff, then ∫abf(x) dx=F(b)−F(a)\displaystyle\int_a^b f(x)\,dx = F(b)-F(a), and explain why the particular antiderivative you choose does not change the answer.
  2. 02Evaluate definite integrals of polynomials, sin⁡x\sin x and cos⁡x\cos x, exe^x, and 1x\dfrac1x by finding an antiderivative FF and computing the clean number F(b)−F(a)F(b)-F(a).
  3. 03Apply the net change theorem ∫abr(t) dt=R(b)−R(a)\displaystyle\int_a^b r(t)\,dt = R(b)-R(a) to read a definite integral of a rate as a total accumulated change, stated with correct units and sign.

Here is the statement in full. Suppose ff is continuous on the closed interval [a, b][a,\,b], and suppose FF is any antiderivative of ff — that is, any function with F ′(x)=f(x)F\,'(x)=f(x). Then the definite integral of ff from aa to bb is the change in FF across the interval: ∫abf(x) dx=F(b)−F(a).\int_a^b f(x)\,dx = F(b)-F(a). The bracket notation [F(x)]ab\left[F(x)\right]_a^b is shorthand for exactly this instruction — evaluate FF at the top limit bb, evaluate it at the bottom limit aa, and subtract the second from the first. No rectangles, no limits of sums; just one antiderivative and one subtraction.

All-Access Plan

6.7 Evaluating definite integrals with the FTC

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