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AP Calculus AB/BC · Mathematics · Lesson 10.3

10.3 The nth-term test for divergence (BC)

Level
Advanced Placement (AP)
Reading time
9 min reading
Errata

Abstract

If the terms themselves do not shrink to zero, there is no way the running total can settle — the series must diverge.

Concept preview

What you will be able to do

  1. 01State the nth-term test for divergence: if lim⁡n→∞an≠0\lim_{n\to\infty} a_n \ne 0 (or the limit does not exist), then the series ∑an\sum a_n diverges.
  2. 02Explain the one-directional logic of the test — why lim⁡n→∞an=0\lim_{n\to\infty} a_n = 0 is necessary for convergence but is NOT sufficient, using the harmonic series as the decisive counterexample.
  3. 03Use the test as a fast first screen on a series, correctly reporting "diverges" or "inconclusive" and never mistakenly concluding convergence from shrinking terms.

A series ∑n=1∞an\sum_{n=1}^{\infty} a_n converges only if its sequence of partial sums SN=a1+a2+⋯+aNS_N = a_1 + a_2 + \cdots + a_N approaches a finite limit as N→∞N\to\infty. Now think about what each new term aNa_N contributes: aN=SN−SN−1a_N = S_N - S_{N-1}. If the partial sums are homing in on a single number SS, then both SNS_N and SN−1S_{N-1} approach that same SS, and their difference aNa_N must approach S−S=0S - S = 0. In other words, convergence FORCES the terms to die out. Turning that statement around gives the test.

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10.3 The nth-term test for divergence (BC)

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