AP Calculus AB/BC · Mathematics · Lesson 10.3
10.3 The nth-term test for divergence (BC)
- Level
- Advanced Placement (AP)
- Reading time
- 9 min reading
- Standard
- Accuracy standard
- Errata
Abstract
If the terms themselves do not shrink to zero, there is no way the running total can settle — the series must diverge.
Concept preview
What you will be able to do
- 01State the nth-term test for divergence: if (or the limit does not exist), then the series diverges.
- 02Explain the one-directional logic of the test — why is necessary for convergence but is NOT sufficient, using the harmonic series as the decisive counterexample.
- 03Use the test as a fast first screen on a series, correctly reporting "diverges" or "inconclusive" and never mistakenly concluding convergence from shrinking terms.
A series converges only if its sequence of partial sums approaches a finite limit as . Now think about what each new term contributes: . If the partial sums are homing in on a single number , then both and approach that same , and their difference must approach . In other words, convergence FORCES the terms to die out. Turning that statement around gives the test.
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10.3 The nth-term test for divergence (BC)
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