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AP Calculus AB/BC · Mathematics · Lesson 10.2

10.2 Geometric series (BC)

Level
Advanced Placement (AP)
Reading time
8 min reading
Errata

Abstract

A geometric series multiplies by the same ratio each term.

Concept preview

What you will be able to do

  1. 01Identify a geometric series ∑n=0∞arn\sum_{n=0}^{\infty} ar^n by its constant ratio rr and first term aa, and derive the partial-sum formula SN=a1−rN1−rS_N=a\dfrac{1-r^{N}}{1-r}.
  2. 02State and apply the convergence criterion: a geometric series converges iff ∣r∣<1|r|<1, in which case its sum is a1−r\dfrac{a}{1-r}; extract aa, rr, or the sum when given the other two.
  3. 03Convert a repeating decimal into a geometric series and sum it to a fraction, and explain why the formula a1−r\dfrac{a}{1-r} is meaningless when ∣r∣≥1|r|\ge 1.

A series is GEOMETRIC when the ratio of consecutive terms is a constant rr: every term equals the previous term times rr. Starting from a first term aa, the terms are a, ar, ar2, ar3,…a,\,ar,\,ar^2,\,ar^3,\ldots, so the series is ∑n=0∞arn=a+ar+ar2+⋯\sum_{n=0}^{\infty} ar^n=a+ar+ar^2+\cdots. Two numbers describe the whole thing: the first term aa and the common ratio rr. You can always recover the ratio by dividing any term by the one before it, r=an+1anr=\dfrac{a_{n+1}}{a_n}; if that quotient is not the same at every step, the series is not geometric and this lesson does not apply.

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10.2 Geometric series (BC)

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