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AP Calculus AB/BC · Mathematics · Lesson 9.5

9.5 Integrating vector-valued functions (BC)

Level
Advanced Placement (AP)
Reading time
9 min reading
Errata

Abstract

Integrating a velocity vector recovers position, one component at a time.

Concept preview

What you will be able to do

  1. 01Integrate a vector-valued function componentwise, writing ∫r⃗(t) dt=⟨∫x(t) dt,  ∫y(t) dt⟩+C⃗\int\vec r(t)\,dt=\left\langle\int x(t)\,dt,\;\int y(t)\,dt\right\rangle+\vec C with a constant VECTOR of integration.
  2. 02Recover a position function from a velocity function by integrating and using an initial condition r⃗(t0)=r⃗0\vec r(t_0)=\vec r_0 to solve for the constant vector.
  3. 03Compute the net displacement over [a,b][a,b] as the definite integral ∫abv⃗(t) dt=r⃗(b)−r⃗(a)\int_a^b\vec v(t)\,dt=\vec r(b)-\vec r(a), and distinguish it from indefinite integration.

A vector-valued function packages two ordinary functions into one moving arrow. Writing r⃗(t)=⟨x(t), y(t)⟩\vec r(t)=\langle x(t),\,y(t)\rangle means that at each time tt the tip of the vector sits at the point (x(t), y(t))\left(x(t),\,y(t)\right), and as tt runs the tip traces a curve in the plane. Earlier in Unit 9 you differentiated such a function by differentiating each component: r⃗ ′(t)=⟨x′(t), y′(t)⟩\vec r\,'(t)=\langle x'(t),\,y'(t)\rangle gives the velocity vector. Integration simply runs that machine in reverse. Because the derivative acts component by component, so does the antiderivative — to integrate a vector-valued function you integrate each component separately and reassemble the results into a new vector.

All-Access Plan

9.5 Integrating vector-valued functions (BC)

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