AP Calculus AB/BC · Mathematics · Lesson 9.1
9.1 Differentiating parametric equations (BC)
- Level
- Advanced Placement (AP)
- Reading time
- 8 min reading
- Standard
- Accuracy standard
- Errata
Abstract
When a curve is traced by and , the slope is still rise over run — but both rise and run are measured against the parameter .
Concept preview
What you will be able to do
- 01Describe a curve given parametrically by and , and explain why such a curve need not be the graph of a single function .
- 02Compute the slope of a parametric curve with the chain-rule formula — dividing the vertical rate by the horizontal rate, not multiplying them.
- 03Locate horizontal tangents where (and ) and vertical tangents where (and ), and evaluate at a chosen value of .
A parametric curve is a pair of equations and sharing one parameter . Think of as time and the pair as the recipe for a point that moves through the plane. For example, and with running over traces an ellipse: at the point sits at , at it is at , at it is at , and it returns to the start at . No single describes this whole loop — for most there are two values — which is exactly why we need the parameter.
All-Access Plan
9.1 Differentiating parametric equations (BC)
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