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AP Calculus AB/BC · Mathematics · Lesson 9.7

9.7 Polar coordinates and differentiation (BC)

Level
Advanced Placement (AP)
Reading time
8 min reading
Errata

Abstract

A polar curve r=f(θ)r=f(\theta) is really a parametric curve: x=rcos⁡θ, y=rsin⁡θx=r\cos\theta,\ y=r\sin\theta.

Concept preview

What you will be able to do

  1. 01Locate and plot points in polar coordinates (r,θ)(r,\theta) and convert between polar and rectangular form using x=rcos⁡θx=r\cos\theta and y=rsin⁡θy=r\sin\theta.
  2. 02Interpret a polar curve r=f(θ)r=f(\theta) and recognise the shapes of circles, roses, and cardioids directly from their equations.
  3. 03Differentiate a polar curve by treating it as a parametric curve in θ\theta, using dydx=(dr/dθ)sin⁡θ+rcos⁡θ(dr/dθ)cos⁡θ−rsin⁡θ\dfrac{dy}{dx}=\dfrac{(dr/d\theta)\sin\theta+r\cos\theta}{(dr/d\theta)\cos\theta-r\sin\theta}, and locate horizontal and vertical tangents.

A polar coordinate pair (r,θ)(r,\theta) names a point by two instructions: face in the direction of angle θ\theta (measured counter-clockwise from the positive xx-axis), then walk a distance rr outward from the origin, called the pole. The point (2, π/3)(2,\,\pi/3), for instance, sits two units out along the ray that makes a 60∘60^\circ angle with the positive xx-axis. Angles are in radians throughout calculus, and a negative rr means "walk backwards" — the point (−2, π/3)(-2,\,\pi/3) lands in the opposite direction, the same place as (2, π/3+π)(2,\,\pi/3+\pi).

All-Access Plan

9.7 Polar coordinates and differentiation (BC)

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