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AP Calculus AB/BC · Mathematics · Lesson 8.3

8.3 Accumulation in applied contexts

Level
Advanced Placement (AP)
Reading time
10 min reading
Errata

Abstract

Any “rate in / rate out” story is an accumulation: integrate the net rate to get the net change, and add it to a starting amount to get the total present at a later time.

Concept preview

What you will be able to do

  1. 01Formulate the "final amount = initial amount + accumulated change" relationship F(b)=F(a)+∫abF′(t) dtF(b)=F(a)+\int_a^b F'(t)\,dt and use it to answer applied questions about tanks, costs, and populations.
  2. 02Interpret a definite integral of a rate as the NET CHANGE of the accumulated quantity over an interval, and attach the correct units to that change.
  3. 03Set up and evaluate accumulation problems from a rate given as a formula, a table, or a graph, without forgetting the initial value.

Suppose a quantity F(t)F(t) changes over time and you know its rate of change F′(t)F'(t) — the derivative. The Fundamental Theorem of Calculus says that adding up the rate over an interval recovers the total change in the quantity: ∫abF′(t) dt=F(b)−F(a)\int_a^b F'(t)\,dt = F(b)-F(a). Read the right-hand side out loud: it is the ending value minus the starting value, which is precisely the net change in FF from t=at=a to t=bt=b. So the definite integral of a rate is a CHANGE, a difference, not the amount itself.

All-Access Plan

8.3 Accumulation in applied contexts

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