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AP Calculus AB/BC · Mathematics · Lesson 4.2

4.2 Straight-line motion: position, velocity, acceleration

Level
Advanced Placement (AP)
Reading time
10 min reading
Errata

Abstract

For motion on a line, velocity is the derivative of position and acceleration is the derivative of velocity.

Concept preview

What you will be able to do

  1. 01Model straight-line motion with a position function s(t)s(t), and compute velocity v(t)=s′(t)v(t)=s'(t) and acceleration a(t)=v′(t)=s′′(t)a(t)=v'(t)=s''(t) as successive derivatives.
  2. 02Use the SIGN of velocity to determine direction of motion and speed ∣v(t)∣|v(t)| to measure how fast, and identify when a particle is at rest (v=0v=0).
  3. 03Decide when a particle is speeding up or slowing down by comparing the signs of vv and aa, and distinguish total distance travelled from displacement.

Picture a particle moving back and forth along a straight line, like a bead on a wire. Its POSITION is given by a function s(t)s(t): a signed coordinate on the line at time tt, where positive means one direction from the origin and negative means the other. Position is a location, not a distance — it can be negative, and the particle can return to a spot it has visited before. Everything we want to know about the motion is encoded in this one function and its derivatives.

All-Access Plan

4.2 Straight-line motion: position, velocity, acceleration

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