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AP Calculus AB/BC · Mathematics · Lesson 2.10

2.10 Derivatives of tan, cot, sec, csc

Level
Advanced Placement (AP)
Reading time
8 min reading
Errata

Abstract

Build the remaining trig derivatives from sin⁡\sin and cos⁡\cos using the quotient rule.

Concept preview

What you will be able to do

  1. 01State the derivatives of tan⁡x\tan x, cot⁡x\cot x, sec⁡x\sec x, and csc⁡x\csc x, and reproduce the co-function minus-sign pattern correctly.
  2. 02Derive ddxtan⁡x=sec⁡2x\frac{d}{dx}\tan x=\sec^2 x and ddxsec⁡x=sec⁡xtan⁡x\frac{d}{dx}\sec x=\sec x\tan x from tan⁡x=sin⁡xcos⁡x\tan x=\frac{\sin x}{\cos x} and sec⁡x=1cos⁡x\sec x=\frac{1}{\cos x} using the quotient rule.
  3. 03Evaluate these derivatives at the standard angles 0, π6, π4, π30,\ \tfrac{\pi}{6},\ \tfrac{\pi}{4},\ \tfrac{\pi}{3} to produce clean numerical values.

The sine and cosine derivatives are the two foundations; the other four trig derivatives are consequences. Because tan⁡x=sin⁡xcos⁡x\tan x=\frac{\sin x}{\cos x}, cot⁡x=cos⁡xsin⁡x\cot x=\frac{\cos x}{\sin x}, sec⁡x=1cos⁡x\sec x=\frac{1}{\cos x}, and csc⁡x=1sin⁡x\csc x=\frac{1}{\sin x} are all quotients of sine and cosine, the quotient rule from 2.9 delivers every one of their derivatives. This lesson derives them so you understand where they come from, then organizes them so you can recall them reliably and evaluate them at the standard exam angles.

All-Access Plan

2.10 Derivatives of tan, cot, sec, csc

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